Post/Author/DateTime	Post
Karui_Kage 07-14-07, 05:59 AM	I've been wondering about this recently, and I can't remember the math necessary to calculate this. Obviously, a character at -9 HP has a 10% chance to stabilize, or die. A character at -6 has a 10% chance to stabilize as well, but he has 4 rounds to attempt it, and a higher chance of success. What is the overall percent chance to stabilize if a character, say, begins at -1? -4? How is this calculated again? I know there must be a thread on it somewhere, but I didn't see one on a search.
Nom 07-15-07, 12:36 AM	Chance to not stabilise is 0.9^(number of rounds 'til death). Thus, -9 round is 0.9, -8 is 0.81, -7 is 0.729, and so on. Subtract this value from 1 to find chance to stabilise. Multiply by 100% to turn it into a percentage.
tricky_bob 07-15-07, 04:54 AM	We use CON scores to determine when a PC will die (14 CON means die at -14) and the CON score determines the %age to stabilize (14%).
Karui_Kage 07-15-07, 04:08 PM	Chance to not stabilise is 0.9^(number of rounds 'til death). Thus, -9 round is 0.9, -8 is 0.81, -7 is 0.729, and so on. Subtract this value from 1 to find chance to stabilise. Multiply by 100% to turn it into a percentage. Thanks! That's just what I was looking for.
Sildatorak 07-17-07, 04:52 PM	Can you tell I'm procrastinating? -9=10% chance to stabilize -8=19% -7=27% -6=34% -5=41% -4=47% -3=52% -2=57% -1=61% 0=infinity billion%