Post/Author/DateTime	Post
Kevtar 03-01-07, 06:59 PM	Hi all, I hate math. How long will it take to fill a 5x5x10' room with water if I have a Decanter of Endless Water and use the Geyser function that creates 30 gallons of water/round? This is assuming that 7.5 gallons of water = 1 Cubic foot of space. This is what I came up with: Volume: 5Wx5Lx10H =250 cubic feet in volume. Gallons of water needed to fill the room: 250(7.5)=1,875 gallons Rate of water:30 gallons/round or 300 gallons/minute Answer62.5 rounds or just over 6 minutes. Is that right? Thanks
Yadot 03-01-07, 07:58 PM	Yes, it is.
stargate525 03-01-07, 08:07 PM	6 minutes and fifteen seconds is correct.
Nathreet 03-01-07, 08:14 PM	yeup 6 minutes and fifteen seconds is correct. Actually 6 minutes and fourteen seconds. Only because there are actually 7.48 gallons in a cubic foot. On average it takes a strength of 14 to hold the decanter of endless water without falling. Someone with a strength of 14 can hold 175lbs. of equipment. 175lbs. spread across a foot wide round stream produces 1.55psi of pressure. That might not seem like much, but against a 2.5' x 8' door that equals over 2 tons of force after the room is completely full. Your room better have a good door. Typical thick stone dungeon walls should have no trouble supporting the 5-1/2 tons pressing against them, though. EDIT: There's another ~3.5psi on the bottom of the door from the weight of the water, for a total of ~5psi at the bottom but still 1.55psi up top. So there is about 5 tons pushing on the door and about 12 tons of force pushing on the walls. There are about 8 tons of water in the room. How does 175lbs. become multiple tons? It's a matter of hydraulics. Engineers use it to lift heavy things all the time. The trade-off is that the object being lifted moves much slower than the source of power.
Solaris 03-01-07, 08:18 PM	..
Fencerboy 03-01-07, 09:14 PM	Meaning 62 1/2 rounds of holding, then some swimming...:eek:
Kevtar 03-01-07, 09:45 PM	yeup Actually 6 minutes and fourteen seconds. Only because there are actually 7.48 gallons in a cubic foot. On average it takes a strength of 14 to hold the decanter of endless water without falling. Someone with a strength of 14 can hold 175lbs. of equipment. 175lbs. spread across a foot wide round stream produces 1.55psi of pressure. That might not seem like much, but against a 2.5' x 8' door that equals over 2 tons of force after the room is completely full. Your room better have a good door. Typical thick stone dungeon walls should have no trouble supporting the 5-1/2 tons pressing against them, though. EDIT: There's another ~3.5psi on the bottom of the door from the weight of the water, for a total of ~5psi at the bottom but still 1.55psi up top. So there is about 5 tons pushing on the door and about 12 tons of force pushing on the walls. There are about 8 tons of water in the room. How does 175lbs. become multiple tons? It's a matter of hydraulics. Engineers use it to lift heavy things all the time. The trade-off is that the object being lifted moves much slower than the source of power. I wonder if a character can activate the decanter and then wedge it securely somewhere while it continues to spew water - or would the decanter deactivate once the PC let go? In any case, I've moved from filling the room with water from a decanter to something less complex. I was particularly interested in making sure I remembered the formula for volume correctly. Here's the important follow-up question? Using the information above (and the fact that the walls are 3 feet thick, if that makes a difference), what is the minimum size of hole the PCs would need to make in order to get the room to stop filling? Can you provide an equation? Thanks!