Post/Author/DateTime	Post
#1 klobbermeister Aug 22, 2014 7:59:05	Hey all,   I am not sure how to interpret the rules for reverting from wildshape when down to 0 hp.  I think it's the example that confuses me: "...if you take 10 damage in animal form and have only 1hp left, you revert and take 9 damage."   1) If you have 1hp left, you *aren't* reverting due to having 0 hp...you have 1hp left.  As such, this is a stupid example.   2) Is this just a poorly worded example where the PC Has 10hp in animal form, takes 19 damage, goes to 0, having 9 (excess) damage  (leaving them 1hp away from being dead outright), and then it is those *negative/excess* hps that transfer back to the PC after the reversion?   Mer?
#2 OutsiderSubtype Aug 22, 2014 8:14:42	Remember that when you wildshape you get the new form's hp in place of your own.    If you remember that the example is easy to understand.   1. You are in wildshape form. The form has 1 hp left. 2. Still in wildshape form, you are hit by an attack that deals 10 damage. 3. You revert to your own form. Your hp become what they were before you wildshaped. You take 9 points of "excess" damage, reducing your new hp by 9.
#3 Thoughts_My_Aim Aug 22, 2014 8:15:23	It is slightly badly worded. I think what it means is "if you have only 1hp left, and you take 10 damage, you revert and take 9 damage".   This isn't the most intuitive way to read the sentence in the actual book, but it's the only one that is compatible with the way the rules are described as working, and it *is* linguistically legitimate - while you and I both instinctively parse the sentence as saying "and have only 1 hp left (after taking 10 damage)" it is as legitimate to read it as saying "and have only 1 hp left (before taking 10 damage)".